1965 AMC 12 Problem 2

Attempt Problem 2 of the 1965 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1965 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

A regular hexagon is inscribed in a circle. The ratio of the length of a side of the hexagon to the length of the shorter of the arcs intercepted by the side is:
1:11:1
1:61:6
1:π1:\pi
3:π3:\pi
6:π6:\pi
Answer: D
Concepts:regular polygonarccircumferenceratio and proportion
Small hint:
Each side of an inscribed regular hexagon equals the circle’s radius
Big hint:
The shorter arc is one sixth of the circumference
Solution:
If the radius is r,r, the hexagon side is r.r. Its intercepted minor arc has length 2πr6=πr3.\frac{2\pi r}{6}=\frac{\pi r}{3}. The ratio is r:(πr3)=3:π.r:(\frac{\pi r}{3})=3:\pi.
Therefore, the correct answer is D.
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