1969 AMC 12 Problem 19

Attempt Problem 19 of the 1969 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1969 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

The number of distinct ordered pairs (x,y),(x,y), where xx and yy have positive integral values satisfying the equation x4y4−10x2y2+9=0,x^4y^4-10x^2y^2+9=0, is:
00
33
44
1212
infinite
Answer: B
Concepts:Diophantine Equationfactoringcounting pairs
Small hint:
Treat x2y2x^2y^2 as one variable
Big hint:
After factoring, translate the possible values into conditions on the positive integer product xyxy
Solution:
Let u=x2y2.u=x^2y^2. Then u2−10u+9=0,(u−1)(u−9)=0. \begin{aligned} u^2-10u+9&=0,\\ (u-1)(u-9)&=0. \end{aligned} Since xx and yy are positive integers, this means xy=1xy=1 or xy=3.xy=3. The pairs are (1,1),(1,1), (1,3),(1,3), and (3,1),(3,1), for a total of 3.3.
Therefore, the correct answer is B.
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