1983 AMC 12 Problem 18

Attempt Problem 18 of the 1983 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1983 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

Let ff be a polynomial function such that, for all real x,x, f(x2+1)=x4+5x2+3. f(x^2+1)=x^4+5x^2+3. For all real x,x, f(x2−1)f(x^2-1) is
x4+5x2+1x^4+5x^2+1
x4+x2−3x^4+x^2-3
x4−5x2+1x^4-5x^2+1
x4+x2+3x^4+x^2+3
none of these
Answer: B
Concepts:polynomialsubstitutionalgebraic manipulation
Small hint:
Rewrite the right side as a polynomial in x2+1x^2+1
Big hint:
Setting t=x2+1t=x^2+1 gives f(t)=t2+3t−1f(t)=t^2+3t-1
Solution:
With t=x2+1,t=x^2+1, x4+5x2+3=(t−1)2+5(t−1)+3=t2+3t−1. \begin{aligned} x^4+5x^2+3 &=(t-1)^2\\ &\quad+5(t-1)+3\\ &=t^2+3t-1. \end{aligned} Hence f(t)=t2+3t−1.f(t)=t^2+3t-1. Substituting t=x2−1t=x^2-1 gives f(x2−1)=(x2−1)2+3(x2−1)−1=x4+x2−3. \begin{aligned} f(x^2-1) &=(x^2-1)^2\\ &\quad+3(x^2-1)-1\\ &=x^4+x^2-3. \end{aligned}
Therefore, the correct answer is B.
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