1983 AMC 12 Problem 9

Attempt Problem 9 of the 1983 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1983 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

In a certain population the ratio of the number of women to the number of men is 1111 to 10.10. If the average (arithmetic mean) age of the women is 3434 and the average age of the men is 32,32, then the average age of the population is
3291032\frac9{10}
32202132\frac{20}{21}
3333
3312133\frac1{21}
3311033\frac1{10}
Answer: D
Concepts:weighted meanratio and proportion
Small hint:
Use groups of 1111 women and 1010 men
Big hint:
Divide 11⋅34+10⋅3211\cdot34+10\cdot32 by the total number of people
Solution:
Using 1111 women and 1010 men, the total of all ages is 11⋅34+10⋅32=694.11\cdot34+10\cdot32=694. Dividing by 2121 people gives 69421=33121.\frac{694}{21}=33\frac1{21}.
Therefore, the correct answer is D.
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