1987 AMC 12 Problem 9

Attempt Problem 9 of the 1987 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1987 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

The first four terms of an arithmetic sequence are a,a, x,x, b,b, 2x.2x. The ratio of aa to bb is
14\frac14
13\frac13
12\frac12
23\frac23
22
Answer: B
Concepts:arithmetic sequencecommon differenceratio
Small hint:
Write all four terms using aa and a common difference
Big hint:
Use the equation relating the second term xx to the fourth term 2x2x
Solution:
Let the common difference be d.d. Then x=a+d, b=a+2d,x=a+d,\ b=a+2d, and 2x=a+3d.2x=a+3d. Thus 2(a+d)=a+3d, 2(a+d)=a+3d, so a=da=d and b=3d.b=3d. Therefore ab=13.\frac{a}{b}=\frac{1}{3}.
Thus the correct answer is B.
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