1993 AMC 12 Problem 18

Attempt Problem 18 of the 1993 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

Al and Barb start their new jobs on the same day. Al’s schedule is 33 work-days followed by 11 rest-day. Barb’s schedule is 77 work-days followed by 33 rest-days. On how many of their first 10001000 days do both have rest-days on the same day?
4848
5050
7272
7575
100100
Answer: E
Concepts:periodic schedulesleast common multiplecounting
Small hint:
The combined schedule repeats every lcm⁡(4,10)\operatorname{lcm}(4,10) days
Big hint:
Within one 2020-day cycle, compare Al’s rest days with Barb’s
Solution:
The combined pattern repeats every 2020 days. Al rests on days 4,4, 8,8, 12,12, 16,16, 20,20, while Barb rests on days 8,8, 9,9, 10,10, 18,18, 19,19, 20.20. Their common rest days are 88 and 20,20, two per cycle. There are 100020=50\frac{1000}{20}=50 cycles, giving 2⋅50=1002\cdot50=100 common rest days. Thus the correct answer is E.
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