1995 AMC 12 Problem 11

Attempt Problem 11 of the 1995 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1995 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

How many base 1010 four-digit numbers, N=a b c d‾,N=\underline{a\,b\,c\,d}, satisfy all three of the following conditions?
(i) 4,000≤N<6,000;4{,}000\le N\lt6{,}000;
(ii) NN is a multiple of 5;5;
(iii) 3≤b<c≤6.3\le b\lt c\le6.
1010
1818
2424
3636
4848
Answer: C
Concepts:countingdivisibility
Small hint:
Determine the possible digits aa and dd from conditions (i) and (ii)
Big hint:
Choose two distinct digits from 3,3, 4,4, 5,5, 66 for b<cb\lt c
Solution:
The thousands digit aa is 44 or 5,5, and divisibility by 55 makes dd either 00 or 5.5. The pair (b,c)(b,c) is obtained by choosing two of 3,3, 4,4, 5,5, 66 in increasing order, giving (42)=6\binom42=6 pairs. Thus the count is 2⋅2⋅6=24,2\cdot2\cdot6=24, and the correct answer is C.
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