1958 AMC 12 Problem 13

Attempt Problem 13 of the 1958 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1958 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

The sum of two numbers is 10;10; their product is 20.20. The sum of their reciprocals is:
110\dfrac1{10}
12\dfrac12
11
22
44
Answer: B
Concepts:symmetry (algebra)fractionalgebraic manipulation
Small hint:
Call the numbers xx and yy, but do not solve for them individually
Big hint:
Use 1x+1y=x+yxy\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}
Solution:
If the numbers are xx and y,y, then 1x+1y=x+yxy=1020=12. \frac1x+\frac1y =\frac{x+y}{xy} =\frac{10}{20} =\frac12.
Therefore, the correct answer is B.
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