1960 AMC 12 Problem 1

Attempt Problem 1 of the 1960 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1960 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

If 22 is a solution (root) of x3+hx+10=0,x^3+hx+10=0, then hh equals:
1010
99
22
−2-2
−9-9
Answer: E
Concepts:polynomialsubstitutionlinear equation
Small hint:
Substitute x=2x=2 into the equation
Big hint:
Solve the resulting linear equation for hh
Solution:
Substituting the given root gives 23+2h+10=0. 2^3+2h+10=0. Thus 2h=−18,2h=-18, so h=−9.h=-9.
Therefore, the correct answer is E.
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