1997 AMC 12 Problem 13

Attempt Problem 13 of the 1997 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

How many two-digit positive integers NN have the property that the sum of NN and the number obtained by reversing the order of the digits of NN is a perfect square?
44
55
66
77
88
Answer: E
Concepts:digitsperfect squares
Small hint:
Write N=10x+yN=10x+y and add its reversal
Big hint:
Determine when 11(x+y)11(x+y), with 1≤x≤91\le x\le9 and 0≤y≤90\le y\le9, can be square
Solution:
The sum is 11(x+y).11(x+y). Since 1≤x+y≤18,1\le x+y\le18, this is square only when x+y=11,x+y=11, giving 121.121. The tens digit xx can be any of 2,3,…,9,2,3,\ldots,9, with y=11−x.y=11-x. There are 88 integers, so E is correct.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.