1998 AMC 12 Problem 13

Attempt Problem 13 of the 1998 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1998 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Walter rolls four standard six-sided dice and finds that the product of the numbers on the upper faces is 144.144. Which of the following could not be the sum of the upper four faces?
1414
1515
1616
1717
1818
Answer: E
Concepts:factorizationcasework
Small hint:
Factor 144=24⋅32144=2^4\cdot3^2 using four factors from 11 through 66
Big hint:
Separate the cases with zero, one, or two faces showing 66
Solution:
Valid rolls include (4,4,3,3)(4,4,3,3) with sum 14,14, (6,4,3,2)(6,4,3,2) with sum 15,15, (6,6,2,2)(6,6,2,2) with sum 16,16, and (6,6,4,1)(6,6,4,1) with sum 17.17. If two 66s occur, the other two faces have product 44 and sum at most 5,5, giving total at most 17;17; the cases with fewer 66s also cannot total 1818 while retaining product 144.144. Thus 1818 is impossible, and E is correct.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.