1952 AMC 12 Problem 8

Attempt Problem 8 of the 1952 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1952 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

Two equal circles in the same plane cannot have the following number of common tangents:
11
22
33
44
None of these
Answer: A
Concepts:circletangent linecasework
Small hint:
Consider intersecting, externally tangent, and disjoint equal circles
Big hint:
An internal tangency would require unequal radii unless the circles coincide
Solution:
Two distinct equal circles have 22 common tangents when they intersect, 33 when externally tangent, and 44 when disjoint. They cannot be internally tangent, because internal tangency requires the center distance to equal the difference of the radii, which is 0.0. At center distance 00 the equal circles coincide and have infinitely many common tangents.
Thus exactly 11 common tangent is impossible, so the correct answer is A.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.