1989 AMC 12 Problem 8

Attempt Problem 8 of the 1989 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

For how many integers nn between 11 and 100100 does x2+x−nx^2+x-n factor into the product of two linear factors with integer coefficients?
00
11
22
99
1010
Answer: D
Concepts:factoringcounting integers in a rangequadratic
Small hint:
Write the factors as (x−r)(x+s)(x-r)(x+s) with positive integers r,sr,s
Big hint:
The coefficient of xx forces the two integer parameters to differ by 11
Solution:
An integer factorization must have the form (x−k)(x+k+1)(x-k)(x+k+1) for some positive integer k.k. Expanding gives x2+x−k(k+1),x^2+x-k(k+1), so n=k(k+1).n=k(k+1). The values k=1,2,…,9k=1,2,\ldots,9 give n≤100,n\le100, while 10⋅11>100.10\cdot11\gt100. There are 99 values.
Thus the correct answer is D.
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