1976 AMC 12 Problem 8

Attempt Problem 8 of the 1976 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1976 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

A point in the plane, both of whose rectangular coordinates are integers with absolute value less than or equal to four, is chosen at random, with all such points having an equal probability of being chosen. What is the probability that the distance from the point to the origin is at most two units?
1381\frac{13}{81}
1581\frac{15}{81}
1364\frac{13}{64}
π16\frac{\pi}{16}
the square of a rational number
Answer: A
Concepts:lattice pointbasic probabilitycirclesystematic listing
Small hint:
There are 99 choices for each coordinate
Big hint:
Count integer pairs satisfying x2+y2≤4x^2+y^2\le4 by considering x=0,x=0, x=±1,x=\pm1, and x=±2x=\pm2
Solution:
There are 92=819^2=81 possible points. Within distance 22 are the origin; the four points (±1,0),(\pm1,0), (0,±1);(0,\pm1); the four points (±1,±1);(\pm1,\pm1); and the four points (±2,0),(\pm2,0), (0,±2).(0,\pm2). Thus 1313 points qualify, for probability 1381.\frac{13}{81}.
Therefore, the correct answer is A.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.