1957 AMC 12 Problem 8

Attempt Problem 8 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

The numbers x,x, y,y, zz are proportional to 2,2, 3,3, 5.5. The sum of x,x, y,y, and zz is 100.100. The number yy is given by the equation y=ax−10.y=ax-10. Then aa is:
22
23\dfrac23
33
52\dfrac52
44
Answer: A
Concepts:ratio and proportionlinear equation
Small hint:
Write x,y,zx,y,z as 2t,3t,5t2t,3t,5t
Big hint:
Their sum determines tt, after which substitute xx and yy into the given equation
Solution:
Let x=2t,x=2t, y=3t,y=3t, and z=5t.z=5t. Since 10t=100,10t=100, we get t=10,t=10, so x=20x=20 and y=30.y=30. Thus 30=20a−10, 30=20a-10, and a=2.a=2.
Therefore, the correct answer is A.
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