1977 AMC 12 Problem 8

Attempt Problem 8 of the 1977 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1977 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

For every triple (a,b,c)(a,b,c) of nonzero real numbers, form the number a∣a∣+b∣b∣+c∣c∣+abc∣abc∣. \frac a{|a|}+\frac b{|b|}+\frac c{|c|}+\frac{abc}{|abc|}. The set of all numbers formed is
{0}\{0\}
{−4,0,4}\{-4,0,4\}
{−4,−2,0,2,4}\{-4,-2,0,2,4\}
{−4,−2,2,4}\{-4,-2,2,4\}
none of these
Answer: B
Concepts:absolute valuecasework
Small hint:
Each of the first three fractions is either 11 or −1-1
Big hint:
The sign of the final fraction is the product of the first three signs
Solution:
Let r,r, s,s, t∈{−1,1}t\in\{-1,1\} be the signs of a,a, b,b, c.c. The expression is r+s+t+rst.r+s+t+rst. If all three signs are positive it is 4,4, and if all are negative it is −4.-4. If the signs are mixed, direct cancellation gives 0.0. Hence the set is {−4,0,4}.\{-4,0,4\}.
Therefore, the correct answer is B.
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