1964 AMC 12 Problem 13

Attempt Problem 13 of the 1964 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1964 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

A circle is inscribed in a triangle with side lengths 8,8, 13,13, and 17.17. Let the segments of the side of length 8,8, made by a point of tangency, be rr and s,s, with r<s.r\lt s. What is the ratio r:s?r:s?
1:31:3
2:52:5
1:21:2
2:32:3
3:43:4
Answer: A
Concepts:incircle, incenter, and inradiustangent lineratio and proportion
Small hint:
Compute the semiperimeter of the triangle
Big hint:
A tangency segment adjacent to a vertex equals the semiperimeter minus the opposite side
Solution:
The semiperimeter is 8+13+172=19.\frac{8+13+17}{2}=19. At the endpoints of the side of length 8,8, the tangent lengths are 19−13=619-13=6 and 19−17=2.19-17=2. Thus r:s=2:6=1:3.r:s=2:6=1:3.
Therefore, the correct answer is A.
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