1955 AMC 12 Problem 25

Attempt Problem 25 of the 1955 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1955 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

One of the factors of x4+2x2+9x^4+2x^2+9 is:
x2+3x^2+3
x+1x+1
x2−3x^2-3
x2−2x−3x^2-2x-3
none of these
Answer: E
Concepts:polynomial factorizationdifference of squares
Small hint:
Rewrite the polynomial as (x2+3)2−(2x)2(x^2+3)^2-(2x)^2
Big hint:
Factor the resulting difference of squares and compare both factors with the choices
Solution:
We have x4+2x2+9=(x2+3)2−(2x)2=(x2−2x+3)⋅(x2+2x+3). \begin{aligned} x^4+2x^2+9 &=(x^2+3)^2\\ &\quad{}-(2x)^2\\ &=(x^2-2x+3)\\ &\quad\cdot(x^2+2x+3). \end{aligned} Neither factor appears among choices A through D.
Thus, the correct answer is E.
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