1959 AMC 12 Problem 25

Attempt Problem 25 of the 1959 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1959 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

The symbol ∣a∣|a| means +a+a if aa is greater than or equal to zero, and −a-a if aa is less than or equal to zero; the symbol <\lt means “less than”; the symbol >\gt means “greater than.” The set of values xx satisfying the inequality ∣3−x∣<4|3-x|\lt4 consists of all xx such that:
x2<49x^2\lt49
x2>1x^2\gt1
1<x2<491\lt x^2\lt49
−1<x<7-1\lt x\lt7
−7<x<1-7\lt x\lt1
Answer: D
Concepts:absolute valueinequality
Small hint:
Rewrite ∣3−x∣<4|3-x|\lt4 as a compound inequality
Big hint:
Solve −4<3−x<4-4\lt3-x\lt4 for xx
Solution:
The absolute-value inequality is equivalent to −4<3−x<4. -4\lt3-x\lt4. Subtracting 33 and multiplying by −1-1 reverses the inequalities, giving −1<x<7. -1\lt x\lt7.
Thus, the correct answer is D.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.