1976 AMC 12 Problem 25

Attempt Problem 25 of the 1976 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1976 AMC 12 solutions, or check the answer key.

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25.

For a sequence u1,u_1, u2,u_2, …,\ldots, define Δ1(un)=un+1−un\Delta^1(u_n)=u_{n+1}-u_n and, for all integers k>1,k\gt1, Δk(un)=Δ1(Δk−1(un)).\Delta^k(u_n)=\Delta^1(\Delta^{k-1}(u_n)). If un=n3+n,u_n=n^3+n, then Δk(un)=0\Delta^k(u_n)=0 for all nn
if k=1k=1
if k=2,k=2, but not if k=1k=1
if k=3,k=3, but not if k=2k=2
if k=4,k=4, but not if k=3k=3
for no value of kk
Answer: D
Concepts:polynomialrecursionpattern recognition
Small hint:
Each forward difference lowers the degree of a polynomial sequence by one
Big hint:
Compute through the constant third difference to see when zero first appears
Solution:
Directly, Δun=3n2+3n+2,Δ2un=6n+6,Δ3un=6,Δ4un=0. \begin{aligned} \Delta u_n&=3n^2+3n+2,\\ \Delta^2u_n&=6n+6,\\ \Delta^3u_n&=6,\\ \Delta^4u_n&=0. \end{aligned} Thus the fourth differences vanish for all n,n, but the third differences do not.
Therefore, the correct answer is D.
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