1978 AMC 12 Problem 8

Attempt Problem 8 of the 1978 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1978 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

If x≠yx\ne y and the sequences x,x, a1,a_1, a2,a_2, yy and x,x, b1,b_1, b2,b_2, b3,b_3, yy each are in arithmetic progression, then a2−a1b2−b1\frac{a_2-a_1}{b_2-b_1} equals
23\frac23
34\frac34
11
43\frac43
32\frac32
Answer: D
Concepts:arithmetic sequenceratio and proportion
Small hint:
Count the equal steps from xx to yy in each sequence
Big hint:
The two common differences are y−x3\frac{y-x}{3} and y−x4\frac{y-x}{4}
Solution:
The first common difference is y−x3,\frac{y-x}{3}, and the second is y−x4.\frac{y-x}{4}. Since x≠y,x\ne y, their ratio is y−x3y−x4=43. \frac{\frac{y-x}{3}}{\frac{y-x}{4}}=\frac43.
Therefore, the correct answer is D.
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