1968 AMC 12 第 34 题

先试着解答 1968 AMC 12 第 34 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1968 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

34.

众议院共有 400400 名议员投票,一项法案未获通过。由同一批议员重新投票后,法案以原先落败票差两倍的票差通过。重新投票时的赞成票数是原先反对票数的 1211\dfrac{12}{11}。第二次投票的赞成票比第一次多多少票?
With 400400 members voting, the House of Representatives defeated a bill. A re-vote, with the same members voting, resulted in passage of the bill by twice the margin by which it was originally defeated. The number voting for the bill on the re-vote was 1211\dfrac{12}{11} of the number voting against it originally. How many more members voted for the bill the second time than voted for it the first time?
7575
6060
5050
4545
2020
答案:B
知识点:方程组比与比例
小提示:
设第一次和第二次投票的赞成票数分别为 FF 和 GG
Let the original and second numbers voting for be FF and GG
大提示:
使用 G=1211(400−F)G=\frac{12}{11}(400-F) 和 2G−400=2(400−2F)2G-400=2(400-2F)
Use G=1211(400−F)G=\frac{12}{11}(400-F) and 2G−400=2(400−2F)2G-400=2(400-2F)
解答:
设第一次和第二次投票的赞成票数为 FF、GG。由比例条件得 G=1211(400−F)G=\frac{12}{11}(400-F)。通过时的票差是原先落败票差的两倍,所以 2G−400=2(400−2F)2G-400=2(400-2F),即 G+2F=600G+2F=600。解得 F=180F=180、G=240G=240,所以第二次多了 6060 张赞成票。
因此,正确答案是 B。
Let F,F, GG be the original and second numbers voting for the bill. The ratio condition gives G=1211(400−F).G=\frac{12}{11}(400-F). The passage margin is twice the original defeat margin, so 2G−400=2(400−2F),2G-400=2(400-2F), or G+2F=600.G+2F=600. Solving gives F=180,F=180, G=240,G=240, so 6060 more members voted for it.
Therefore, the correct answer is B.
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