1990 AMC 12 Problem 25

Attempt Problem 25 of the 1990 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 12 solutions, or check the answer key.

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25.

Nine congruent spheres are packed inside a unit cube in such a way that one of them has its center at the center of the cube and each of the others is tangent to the center sphere and to three faces of the cube. What is the radius of each sphere?
1−321-\frac{\sqrt3}{2}
23−32\frac{2\sqrt3-3}{2}
26\frac{\sqrt2}{6}
14\frac14
3(2−2)4\frac{\sqrt3(2-\sqrt2)}4
Answer: B
Concepts:three-dimensional geometrydistance formulatangent spheres
Small hint:
Place one corner sphere’s center at (r,r,r)(r,r,r)
Big hint:
Its distance from (12,12,12)(\frac{1}{2},\frac{1}{2},\frac{1}{2}) equals 2r2r
Solution:
If the radius is r,r, a corner sphere has center (r,r,r)(r,r,r) and the central sphere has center (12,12,12).(\frac{1}{2},\frac{1}{2},\frac{1}{2}). Tangency gives 3(12−r)=2r. \sqrt3\left(\frac12-r\right)=2r. Solving and rationalizing, r=32(2+3)=23−32. r=\frac{\sqrt3}{2(2+\sqrt3)} =\frac{2\sqrt3-3}{2}.
Thus the correct answer is B.
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