1973 AMC 12 第 34 题

先试着解答 1973 AMC 12 第 34 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1973 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

34.

一架飞机逆风直飞两座城镇之间,耗时 8484 分钟;顺风返回所需时间比无风时少 99 分钟。返程所需的分钟数(有两个答案)为
A plane flew straight against a wind between two towns in 8484 minutes and returned with that wind in 99 minutes less than it would take in still air. The number of minutes (two answers) for the return trip was
5454 或 1818
5454 or 1818
6060 或 1515
6060 or 1515
6363 或 1212
6363 or 1212
7272 或 3636
7272 or 3636
7575 或 2020
7575 or 2020
答案:C
知识点:路程、速度与时间二次方程方程组
小提示:
设返程时间为 xx;则无风时的飞行时间为 x+9x+9
Let xx be the return time; the still-air time is then x+9x+9
大提示:
飞机在无风时的速度是逆风与顺风地速的平均值
The plane’s still-air speed is the average of its against-wind and with-wind ground speeds
解答:
设两城距离为 dd,返程时间为 xx 分钟。逆风与顺风速度分别为 d84\frac{d}{84} 与 dx\frac{d}{x}。它们的平均值是无风速度 dx+9\frac{d}{x+9}。因此 2x+9=184+1x。 \frac{2}{x+9}=\frac1{84}+\frac1x\text{。}清除分母,得到 168x=(x+9)(x+84),x2−75x+756=0,(x−63)(x−12)=0。 \begin{gathered} 168x=(x+9)(x+84),\\ x^2-75x+756=0,\\ (x-63)(x-12)=0 \end{gathered}\text{。}两个正值都符合题设条件,所以两个返程时间为 6363 分钟与 1212 分钟。
所以正确答案是 C。
Let the distance be dd and the return time be xx minutes. The against-wind and with-wind speeds are d84\frac{d}{84} and dx.\frac{d}{x}. Their average is the still-air speed dx+9.\frac{d}{x+9}. Therefore 2x+9=184+1x. \frac{2}{x+9}=\frac1{84}+\frac1x. Clearing denominators gives 168x=(x+9)(x+84),x2−75x+756=0,(x−63)(x−12)=0. \begin{gathered} 168x=(x+9)(x+84),\\ x^2-75x+756=0,\\ (x-63)(x-12)=0. \end{gathered} Both positive values are consistent with the stated conditions, so the two return times are 6363 and 1212 minutes.
Therefore, the correct answer is C.
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