1962 AMC 12 第 35 题

先试着解答 1962 AMC 12 第 35 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1962 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

35.

某人在下午 6:006{:}00 刚过不久外出赴宴时,看到手表的时针与分针成 110∘110^\circ 角。他在下午 7:007{:}00 前返回时,发现两根指针再次成 110∘110^\circ 角。他离开的分钟数为:
A man on his way to dinner shortly after 6:006{:}00 p.m. observes that the hands of his watch form an angle of 110∘.110^\circ. Returning before 7:007{:}00 p.m. he notices that again the hands of his watch form an angle of 110∘.110^\circ. The number of minutes that he has been away is:
362336\dfrac23
4040
4242
42.442.4
4545
答案:B
知识点:时钟相对速度
小提示:
在这段时间内,分针每分钟比时针多转 5.5∘5.5^\circ
During the interval, the minute hand gains on the hour hand at 5.5∘5.5^\circ per minute
大提示:
两次观察之间,带符号的角度差从 110∘110^\circ 变为 −110∘-110^\circ
Between the two observations, the signed separation changes from 110∘110^\circ to −110∘-110^\circ
解答:
两次观察分别位于两针重合时刻的前后两侧。带符号的角度差变化了 220∘220^\circ。由于分针每分钟比时针多转 6−0.5=5.5∘6-0.5=5.5^\circ,所以经过的时间为 2205.5=40 \frac{220}{5.5}=40 分钟。
所以正确答案是 B。
The two observations lie on opposite sides of the instant when the hands coincide. Their signed angular separation changes by 220∘.220^\circ. Since the minute hand gains on the hour hand at 6−0.5=5.5∘6-0.5=5.5^\circ per minute, the elapsed time is 2205.5=40 \frac{220}{5.5}=40 minutes.
Thus, the correct answer is B.
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