1958 AMC 12 第 15 题

先试着解答 1958 AMC 12 第 15 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1958 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

一个四边形内接于圆。在四边形外部的四个弓形中各作一个圆周角,则这四个角的度数之和为:
A quadrilateral is inscribed in a circle. If an angle is inscribed into each of the four segments outside the quadrilateral, the sum of these four angles, expressed in degrees, is:
10801080
900900
720720
540540
360360
答案:D
知识点:圆内接四边形圆周角弧角度和
小提示:
四边形各边所截的四段弧的度数之和为 360∘360^\circ
Let the four arcs cut off by the quadrilateral’s sides have measures summing to 360∘360^\circ
大提示:
位于某边外侧弓形内的圆周角所对的是互补的优弧
An angle in the outside segment of a side subtends the complementary major arc
解答:
设各边所截的四段劣弧度数为 α1,…,α4\alpha_1,\ldots,\alpha_4,其和为 360∘360^\circ。与弧 αi\alpha_i 对应的外侧弓形内的圆周角所对的是另一段弧,因此其度数为 360∘−αi2。 \frac{360^\circ-\alpha_i}{2}\text{。}所以四个角的度数之和为 4(360∘)−360∘2=540∘。 \frac{4(360^\circ)-360^\circ}{2}=540^\circ\text{。}
所以正确答案为 D。
Let the four minor arcs cut off by the sides have measures α1,…,α4,\alpha_1,\ldots,\alpha_4, whose sum is 360∘.360^\circ. The angle in the outside segment corresponding to arc αi\alpha_i subtends the other arc, so its measure is 360∘−αi2. \frac{360^\circ-\alpha_i}{2}. The sum of the four angles is therefore 4(360∘)−360∘2=540∘. \frac{4(360^\circ)-360^\circ}{2}=540^\circ.
Thus, the correct answer is D.
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