1951 AMC 12 第 2 题

先试着解答 1951 AMC 12 第 2 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1951 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

一块长方形田地的宽是长的一半,四周共用 xx 码栅栏围住。用 xx 表示其面积为:
A rectangular field is half as wide as it is long and is completely enclosed by xx yards of fencing. The area in terms of xx is:
x22\dfrac{x^2}{2}
2x22x^2
2x29\dfrac{2x^2}{9}
x218\dfrac{x^2}{18}
x272\dfrac{x^2}{72}
答案:D
知识点:矩形周长面积
小提示:
设宽为 ww,则长为 2w2w
Let the width be ww, so the length is 2w2w
大提示:
求面积前,先使用周长方程 2(w+2w)=x2(w+2w)=x
Use the perimeter equation 2(w+2w)=x2(w+2w)=x before finding the area
解答:
设宽为 ww,则长为 2w2w。由栅栏总长可得 2(w+2w)=6w=x2(w+2w)=6w=x,所以 w=x6w=\frac{x}{6}。因此, A=w(2w)=2(x6)2=x218。 A=w(2w)=2\left(\frac{x}{6}\right)^2=\frac{x^2}{18}\text{。}
因此,正确答案是 D。
Let the width be ww, so the length is 2w.2w. The fencing gives 2(w+2w)=6w=x,2(w+2w)=6w=x, hence w=x6.w=\frac{x}{6}. Therefore A=w(2w)=2(x6)2=x218. A=w(2w)=2\left(\frac{x}{6}\right)^2=\frac{x^2}{18}.
Thus, the correct answer is D.
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