1959 AMC 12 第 29 题
先试着解答 1959 AMC 12 第 29 题，然后核对你的答案与精心整理的解答，解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1959 AMC 12 解答，或核对答案。
所有题目均经美国数学协会（MAA）官方合法授权使用。
29.
一场考试共有 道题，一名学生在前 道题中答对了 道，其余题目中答对了三分之一。每道题分值相同。若该生得分为 ，则 有多少个不同的可能值？
On an examination of questions a student answers correctly of the first Of the remaining questions he answers one third correctly. All the questions have the same credit. If the student’s mark is how many different values of can there be?
无法确定
the problem cannot be solved
小提示：
用 表示答对的总题数
Express the total number correct in terms of
大提示：
令 等于
Set equal to
解答：
得分条件给出 两边乘以 得 ，所以 。此值也使其余题目中答对的题数为整数。因此 恰有一个可能值。
因此，正确答案是 D。
The score condition gives Multiplying by yields so This value also makes the number of remaining correct answers an integer. Hence there is exactly one possible value of
Therefore, the correct answer is D.
其他年份的第 29 题
- 1950 AMC 12
- 1951 AMC 12
- 1952 AMC 12
- 1953 AMC 12
- 1954 AMC 12
- 1955 AMC 12
- 1956 AMC 12
- 1957 AMC 12
- 1958 AMC 12
- 1960 AMC 12
- 1961 AMC 12
- 1962 AMC 12
- 1963 AMC 12
- 1964 AMC 12
- 1965 AMC 12
- 1966 AMC 12
- 1967 AMC 12
- 1968 AMC 12
- 1969 AMC 12
- 1970 AMC 12
- 1971 AMC 12
- 1972 AMC 12
- 1973 AMC 12
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- 1975 AMC 12
- 1976 AMC 12
- 1977 AMC 12
- 1978 AMC 12
- 1979 AMC 12
- 1980 AMC 12
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- 1986 AMC 12
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- 1988 AMC 12
- 1989 AMC 12
- 1990 AMC 12
- 1991 AMC 12
- 1992 AMC 12
- 1993 AMC 12
- 1994 AMC 12
- 1995 AMC 12
- 1996 AMC 12
- 1997 AMC 12
- 1998 AMC 12
- 1999 AMC 12