1989 AMC 12 第 12 题

先试着解答 1989 AMC 12 第 12 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1989 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

某东西向公路上,两个方向的车流均以每小时 6060 英里的恒定速度行驶。一名向东行驶的司机在五分钟内经过 2020 辆向西行驶的车。假设向西车道中的车辆等距排列。下列哪个数最接近一段 100100 英里公路上向西行驶车辆的数量?
The traffic on a certain east-west highway moves at a constant speed of 6060 miles per hour in both directions. An eastbound driver passes 2020 westbound vehicles in a five-minute interval. Assume vehicles in the westbound lane are equally spaced. Which of the following is closest to the number of westbound vehicles present in a 100100-mile section of highway?
100100
120120
200200
240240
400400
答案:C
知识点:相对速度路程、速度与时间比与比例
小提示:
两车接近的相对速度等于它们速度之和
The cars approach one another at the sum of their speeds
大提示:
用相对速度下行驶的距离求向西车辆的间距
Use the distance covered at relative speed to find the spacing between westbound vehicles
解答:
相对速度为每小时 120120 英里,所以五分钟内司机相对行驶 1010 英里。在这段距离内经过 2020 辆等距车辆,间距约为 1020=12\frac{10}{20}=\frac{1}{2} 英里。因此一段 100100 英里的公路约有 10012=200\frac{100}{\frac{1}{2}}=200 辆车。
所以正确答案是 C。
The relative speed is 120120 miles per hour, so in five minutes the driver covers 1010 relative miles. Passing 2020 equally spaced vehicles in that distance means the spacing is about 1020=12\frac{10}{20}=\frac{1}{2} mile. Thus a 100100-mile section contains about 10012=200\frac{100}{\frac{1}{2}}=200 vehicles.
Thus the correct answer is C.
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