1975 AMC 12 第 17 题

先试着解答 1975 AMC 12 第 17 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1975 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

一名男子上下班可以乘火车或公交车。如果早晨乘火车上班,他下午就乘公交车回家;如果下午乘火车回家,他早晨就乘公交车上班。在总共 xx 个工作日中,他早晨乘公交车上班 88 次,下午乘公交车回家 1515 次,并且共乘火车通勤(早晨或下午)99 次。求 xx。
A man can commute either by train or by bus. If he goes to work on the train in the morning, he comes home on the bus in the afternoon; and if he comes home in the afternoon on the train, he took the bus in the morning. During a total of xx working days, the man took the bus to work in the morning 88 times, came home by bus in the afternoon 1515 times, and commuted by train (either morning or afternoon) 99 times. Find x.x.
1919
1818
1717
1616
所给信息不足以求解
not enough information given to solve the problem
答案:D
知识点:基本计数
小提示:
每个工作日恰有两次单程通勤
There are exactly two one-way trips on every working day
大提示:
将所有公交车行程和火车行程合并计数
Count all bus trips and all train trips together
解答:
公交车行程共有 8+15=238+15=23 次,火车行程共有 99 次,因此单程通勤一共 3232 次。每个工作日对应两次行程,所以 2x=322x=32,从而 x=16x=16。题中的条件相互一致,但这次计数并不需要用到它们。
因此,正确答案是 D。
There were 8+15=238+15=23 bus trips and 99 train trips, hence 3232 one-way trips in all. Since each working day contributes two trips, 2x=322x=32 and x=16.x=16. The conditional statements are consistent but not needed for this count.
Therefore, the correct answer is D.
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