1988 AMC 12 第 12 题

先试着解答 1988 AMC 12 第 12 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1988 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

将整数 11 到 99 分别写在九张纸条上,再把它们全部放入一顶帽子中。杰克随机抽出一张纸条后放回。然后吉尔再随机抽一张。杰克与吉尔所抽整数之和的个位数字最有可能是哪一个?
Each integer 11 through 99 is written on a separate slip of paper and all nine slips are put into a hat. Jack picks one of these slips at random and puts it back. Then Jill picks a slip at random. Which digit is most likely to be the units digit of the sum of Jack’s integer and Jill’s integer?
00
11
88
99
每个数字的可能性都相同
each digit is equally likely
答案:A
知识点:probability模运算counting ordered pairs
小提示:
共有 8181 个等可能的有序数对
There are 8181 equally likely ordered pairs
大提示:
分别数出和对 1010 取各个余数的数对数量
Count pairs whose sum has each residue modulo 1010
解答:
要使个位数字为 00,有序数对为 (1,9),(2,8),…,(9,1)(1,9),(2,8),\ldots,(9,1),共有 99 对。其他每个个位数字都出现 88 次,而全部有序数对共有 8181 个。因此,00 最有可能。
所以正确答案是 A。
For a units digit of 0,0, the ordered pairs are (1,9),(2,8),…,(9,1),(1,9),(2,8),\ldots,(9,1), giving 99 pairs. Each other units digit occurs 88 times among the 8181 ordered pairs. Therefore 00 is most likely.
Thus the correct answer is A.
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