1993 AMC 12 第 8 题

先试着解答 1993 AMC 12 第 8 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1993 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

设 C1C_1 和 C2C_2 是同一平面内两个半径为 11 且互相相切的圆。该平面内有多少个半径为 33 且同时与 C1C_1 和 C2C_2 相切的圆?
Let C1C_1 and C2C_2 be circles of radius 11 that are in the same plane and tangent to each other. How many circles of radius 33 are in this plane and tangent to both C1C_1 and C2?C_2?
22
44
55
66
88
答案:D
知识点:相切圆circle intersections分类讨论
小提示:
半径为 33 的圆与每个单位圆都可能内切或外切。
A radius-33 circle can be internally or externally tangent to each unit circle
大提示:
对它的圆心,考察距离对 (4,4)(4,4)、(2,2)(2,2)、(4,2)(4,2) 和 (2,4)(2,4)。
For its center, consider distance pairs (4,4),(4,4), (2,2),(2,2), (4,2),(4,2), and (2,4)(2,4)
解答:
两个相切单位圆的圆心相距 22 个单位。若新圆与单位圆外切,其圆心到单位圆圆心的距离必须为 44;若内切,则为 22。距离对 (4,4)(4,4) 给出两个圆心,(2,2)(2,2) 也是如此。混合距离对 (4,2)(4,2) 和 (2,4)(2,4) 各给出一个圆心,因为相应的圆心轨迹圆内切。因此共有 2+2+1+1=62+2+1+1=6 个圆。故正确答案是 D。
Let the centers of the tangent unit circles be 22 units apart. The new center must be 44 units from a unit-circle center for external tangency and 22 units away for internal tangency. The distance pair (4,4)(4,4) gives two centers, as does (2,2).(2,2). Each mixed pair (4,2)(4,2) and (2,4)(2,4) gives one center because the corresponding center-circles are internally tangent. Hence there are 2+2+1+1=62+2+1+1=6 circles. Thus the correct answer is D.
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